Subject: Re: group by number
From: Frederic Laurent <fl@xxxxxxxxxxxxx>
Date: Fri, 28 Nov 2003 15:38:47 +0100
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Andreas Lindahl wrote:
> Hi
>
> I have an xml file which looks pretty much like this:
>
<snip/>
> Each group node should contain three item nodes.
>
> How should I do this with XSLT?
use the position function...
I set the root node to result
<xsl:template match="/">
<result>
<xsl:apply-templates select="//item" mode="test"/>
</result>
</xsl:template>
<xsl:template match="item" mode="test">
<xsl:if test="position() mod 3 = 1">
<group id="{ceiling(position() div 3)}">
<xsl:apply-templates select="."/>
<xsl:apply-templates select="following-sibling::item[1]"/>
<xsl:apply-templates select="following-sibling::item[2]"/>
</group>
</xsl:if>
</xsl:template>
<xsl:template match="item">
<xsl:copy><xsl:apply-templates select="*|@*|text()"/></xsl:copy>
</xsl:template>
----
java org.apache.xalan.xslt.Process -IN items.xml -XSL items.xsl
<?xml version="1.0" encoding="UTF-8"?>
<result>
<group id="1">
<item>1</item>
<item>2</item>
<item>3</item>
</group>
<group id="2">
<item>4</item>
<item>5</item>
<item>6</item>
</group>
<group id="3">
<item>7</item>
<item>8</item>
<item>9</item>
</group>
</result>
HTH
cheers
--
XPath free testing software : http://lantern.sourceforge.net
Frédéric Laurent http://www.opikanoba.org
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
- group by number
- Andreas Lindahl - Fri, 28 Nov 2003 08:11:42 -0500 (EST)
- <Possible follow-ups>
- Frederic Laurent - Fri, 28 Nov 2003 09:38:38 -0500 (EST) <=
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