Just two things to note:

 1. The provided source xml is severely non-wellformed.

 2. It is not clear what are the requirements for the transformation

A complete (but smaller) example with well-formed xml and a good
explanation of the requirements for the transformation will have better
chances to be understood.


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL


--- Dongling Ding wrote:
> I have the following XML file and want to sort
> elements based on an attribute in the same level,
> Also, output the non-duplicate elements.
> 
> <Member _pos="1" name="P1" > 
>    <Data> 123</Data>
>    <Member _pos="2" name="P12"> 
> 	<Data> 213</DataStorage>
> 	<Member _pos="3" name="P121"> 
> 		<Data> 666</Data>
> 	</Member> 
>    </Member> 
> </Member> 
> <Member _pos="1" name="P1"> 
>    <DataS> 123</Data>
>    <Member _pos="1" name="P11"> 
>    <Data> 678</DataS>
>    </Member> 
>    <Member _pos="2" name="P12"> 
> 	<Data> 213</Data>
>    </Member> 
> </Member> 
> <Member _pos="2" name="P2"> 
>    <DataS> 4545</Data>
>    <Member _pos="1" name="P21"> 
>    <Data> 678</DataS>
>    </Member> 
>    <Member _pos="2" name="P22"> 
> 	<Data> 213</Data>
>    </Member> 
> </Member> 
> ...
> ...
> 
> What I need in this case is:
> 
> <Member _pos="1" name="P1"> 
>    <DataS> 123</Data>
>    <Member _pos="1" name="P11"> 
>    <Data> 678</DataS>
>    </Member> 
>    <Member _pos="2" name="P12"> 
> 	<Data> 213</Data>
>         <Member _pos="1" name="P121"> 
>           <Data> 666</Data>
>         </Member> 
>    </Member> 
> </Member> 
> <Member _pos="2" name="P2"> 
>    <DataS> 4545</Data>
>    <Member _pos="1" name="P21"> 
>    <Data> 678</DataS>
>    </Member> 
>    <Member _pos="2" name="P22"> 
> 	<Data> 213</Data>
>    </Member> 
> </Member> 
> 
> 
> The requirement is somehow described as follows:
> 
> 1. Sort based on "_pos" in each level of tree
> structure.
> 
> 2. For each level, output the elements without
> duplicate element.
> 
> It is involved the recursive call, sorting and merge.
> If anyone has a good idea for this, please lete me
> know. Very appreciated!!





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