I think you can use a normal matches statement calling a template and then
use xsl:copy-of to keep the subs.

PA Sport RnD

Andrew Curry
Software Developer

Telephone: 01430 455545
Website:        http://www.pa.press.net

PA News Limited:
Bridgegate, Howden, East Yorkshire, DN14 7AE

Registered Office:
PA News Limited, 292 Vauxhall Bridge Road, London SW1V 1AE. Registered in
England No. 3891053


----- Original Message ----- 
From: "Judith Rog" <Judith.Rog@xxxxx>
To: <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, October 07, 2003 12:46 PM
Subject:  xsl:value-of select : how to make some tags printed and
othersnot


> Hi,
> Could anyone help me with the following?
>
> Suppose I have the following XML:
>
> <book>
>    <title>My first book</title>
>    <chapter>
>      <nr>1</nr>
>      <text> This is the <sw>content</sw> of my first book, where
> <sub>I</sub> would like to leave in the sub-tag, but leave out the
> sw-tag.</text>
>    </chapter>
> </book>
>
> Is it possible to make an xsl statement that would print the content of
> the <text> tag and all sub tags (<xsl:value of select="text"/>) but then
> somehow leave the html formatting tags <sub> in the output? So:
> This is the content of my first book, where <sub>I</sub> would like to
> leave in the sub-tag, but leave out the sw-tag.
> instead of:
> This is the content of my first book, where I would like to leave in
> the sub-tag, but leave out the sw-tag.
>
> Thanks for your help.
> Judith
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list