Hi 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Whitney, Dan (CanWest Interactive)
> Sent: Wednesday, October 15, 2003 4:06 PM
> To: 'mulberry - xsl'
> Subject:  creating html tables from cells
> 
> 
> 2 questions.
> 
(...)
> 
> I'm wondering if there's an effecient way with xsl to 
> transform it to: <table>
>   <tr>
>     <td>Row 1 - Column 1</td>
>     <td>Row 1 - Column 2</td>
>     <td>Row 1 - Column 3</td>
>     <td>Row 1 - Column 4</td>
>   </tr>
>   <tr>
>     <td>Row 2 - Column 1</td>
>     <td>Row 2 - Column 2</td>
>     <td>Row 2 - Column 3</td>
>     <td>Row 2 - Column 4</td>
>   </tr>
> </table>
> 
> I know I have to somehow create the tr's on the RS element 
> but I'm not at all sure how.
> 
You can use keys to do this, though it might not be the best solution
for big files.
Check the comments in the code

Stylesheet:
  <!-- set the key to look for the closest previous RI with @col=1 -->
  <xsl:key match="RI" name="RI" use="generate-id((preceding-sibling::RI
| self::RI)[@col=1][last()])"/>

  <xsl:template match="RS">
    <table>
      <!-- start only with RI the belong to the first column -->
      <xsl:apply-templates mode="start" select="RI[@col=1]"/>
    </table>
  </xsl:template>

  <xsl:template match="RI" mode="start">
    <!-- for each one create a row -->
    <tr>
      <!-- then select the nodes until the next RI[@col=1] -->
      <xsl:apply-templates select="key('RI',generate-id())"/>
    </tr>
  </xsl:template>

  <xsl:template match="RI">
    <!-- here you do whatever you want with the columns -->
    <td>
      <xsl:apply-templates/>
    </td>
  </xsl:template>

Regards,
Americo Albuquerque


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