Subject: RE: Replace characters in a node and all of its descendents
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Tue, 30 Sep 2003 17:41:50 +0100
|
Try saxon:serialize(), followed by one of the many ways of doing string
replacement to double the quotes. Or you could write a similar extension
function for a different processor. People have in the past posted code
that does serialization in XSLT itself, and then uses
disable-output-escaping to prevent the markup being escaped, but I
wouldn't recommend it myself.
> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of
> Sergiu Ignat
> Sent: 30 September 2003 16:30
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Replace characters in a node and all of its descendents
>
>
> I need to generate an SQL "INSERT INTO" statement from an xml
> document. One of the columns must hold the string
> representation of an XML node with all of its descendents. To
> insert this node as a string I must replace each single quote
> with other two single quotes for conformance with SQL syntax.
>
> I can not send a deep copy of the node taken with
> <xsl:copy-of> to the $text parameter of the "replace-string"
> template posted by Evan Lenz at
> http://www.dpawson.co.uk/xsl/sect2/replace.htm> l
> How can I get
> a deep copy of a node as a string to process
> it? Multiple transformations are not recomended. Thanks. Sergiu Ignat
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|