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Hi Jeni,
I like this idea, because I would be able to use my current method of indexing to print the line for tables that get sorted and ones that don't. Coming from a C perspective I get to reuse my current funtion! Yeah :).This is a tough problem. To be honest, I'd approach it using two steps: one to do the sorting and the other to arrange the columns. In other words, create an intermediate representation like: However, I'm rather new to XSLT and I don't know how I would generate that intermediate representation. I was under the impression that you could only have a <xsl:sort> element under a <xsl:for-each> element, but upon consulting my big XML book, I see that you can have one under an <xsl:apply-templates> element. So my question is, where would I put the sort statement? Would I put it under my <xsl:apply-templates select="person"/> statement? And doing that would sort all the children elements of <person> according to their refDate attributes correct? Thanks for your help, --Ryan XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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