Even when trying to replace with the " with a single character it does
not work.

Example

 <xsl:element name = "OrganizationCode">
 	<xsl:text>"</xsl:text>
 	<xsl:value-of select =
 "translate(../@OrganizationCode,'\"','B'"/>
 	<xsl:text>"</xsl:text>
 </xsl:element>

-----Original Message-----
From: Passin, Tom [mailto:tpassin@xxxxxxxxxxxx] 
Sent: Monday, September 22, 2003 4:01 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Replacing double quotes with XSLT

[ James Paul]

> I'm trying to replace " within a string in XSLT and replace it with ""
> but I'm not having any luck.
> 
> Does NOT work
> 
> <xsl:element name = "OrganizationCode">
> 	<xsl:text>"</xsl:text>
> 	<xsl:value-of select =
> "translate(../@OrganizationCode,'\"','\"\"'"/>
> 	<xsl:text>"</xsl:text>
> </xsl:element>
> 
> Does NOT work
> 
> <xsl:element name = "OrganizationCode">
> 	<xsl:text>"</xsl:text>
> 	<xsl:value-of select =
> "translate(../@OrganizationCode,'&#x22','&#x22&#x22'"/>
> 	<xsl:text>"</xsl:text>
> </xsl:element>
> 
> Does anyone have any suggestions ???
> 

Both methods fail because translate() replaces one character with
another single character.  You have to write a recursive template - it
is not hard.  See Dave Pawson's FAQ pages, especially

http://www.dpawson.co.uk/xsl/sect2/StringReplace.html

Cheers,

Tom P

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list