Subject: Re: newbie needs help
From: Abhijit Junnare <mavlaabhi@xxxxxxxxx>
Date: Thu, 11 Sep 2003 12:43:01 -0700 (PDT)
|
May be this would work for you
<xsl:template match="document">
<document>
<xsl:copy-of select="form|.//document/link"/>
</document>
</xsl:template>
Abhi
--- Brian Benson <bbenson@xxxxxxxxxxxx> wrote:
>
> Thanks David.
>
> The code you wrote for me, did exactly what I asked
> for. Unfortunately, I
> didn't ask a specific enough question.
>
> Not all documents in the source xml file contain
> links and I want the
> output xml to only contain documents that have
> links. How can the template
> below be changed to only output documents that
> contain links.
>
>
>
>
>
> <xsl:template match="document">
> <document>
> <xsl:copy-of select="form|.//link"/>
> </document>
> </xsl:template>
>
> David
>
>
>
> =======================================
>
> This is probably easy for someone who knows what
> they are doing, but I
> haven't been able to figure this out.
>
> I'm trying to transform XML to XML. The end result
> I want is something
> like:
>
> <document>
> <form>forminfo</form>
> <link>linkinfo</link>
> </document>
>
>
> The problem that I'm having is this: in the source
> xml file, the <form>
> information is always at the same level in the
> source document, but the
> <link> information can be any number of levels deep.
>
> For example it could look like this:
>
> <document>
> <form>forminfo</form>
> <link>linkinfo</link>
> </document>
>
> or it could look like this:
>
> <document>
> <form>forminfo</form>
> <table>
> <link>linkinfo</link>
> </table>
> </document>
>
>
> or like this:
>
> <document>
> <form>forminfo</form>
> <table>
> <table>
> <link>linkinfo</link>
> </table>
> </table>
> </document>
>
>
> I need to find a way to ignore all of the levels of
> table information and
> just get the form and the link information in my
> output file. Any help is
> appreciated.
>
>
>
>
>
>
>
>
>
> XSL-List info and archive:
> http://www.mulberrytech.com/xsl/xsl-list
>
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