Subject: RE: Using a reference in a sort
From: "Jesse M. Heines" <heines@xxxxxxxxxx>
Date: Tue, 29 Jul 2003 19:37:51 -0400
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> Try <xsl:sort
>
select="document($filePeople)/people/person[@id=current()/person/@id]/@l
ast"
> order="descending"/> instead
Thanks for your reply, but I'm sorry to report that that doesn't work
either. The context of current() is still the node in the other XML
file. The documentation I have says that current() is the same as ".",
which I tried and does not help, either.
More suggestions, please!
Jesse
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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