Guten Tag Dave,
Thanks for your email. I think I have been trying to make my problem more
complicated than it actually was - I think David Carlisle has solved it for
me!

Guten Abend;-)
Chris

> -----Original Message-----
> From: David Ohlemacher [mailto:ohlemacher@xxxxxxx] 
> Sent: 18 July 2003 16:19
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re:  Sorting and re-ordering down a hierarchy
> 
> 
> Hi Chris,
> 
> Sorry, I have no help. I tried to do this and failed.  I finally 
> reevaluated the tool (DAML/XSLT Adapter 
> <http://www.daml.org/tools/#damlxslt>) that generated my 
> self-referencing data, and tossed it.   I found Perl, 
> operating on the 
> DAML data directly, was SO much simpler.   Also the tool's author was 
> not helpful.
> 
> After a wasted week of learning XSL (it was a waste for me, no flames 
> please), it took me about 4 hours to write this in Perl.   
> The tool made 
> the work more difficult since it "introduced" the self 
> referencing.  The 
> DAML was simpler. 
> 
> Guten Tag,
> -d
> 
> Cole, Chris wrote:
> 
> >Hello,
> > I'm struggling to re-organise my node tree.
> > My tree is something like this:
> >
> ><input>
> ><node>
> >    <rank>2</rank>
> >    <node>
> >        <rank>88</rank>
> >    </node>
> >    <node>
> >        <rank>7</rank>
> >    </node>
> >    <node>
> >        <rank>66</rank>
> >    </node>
> ></node>
> ><node>
> >    <rank>1</rank>
> >    <node>
> >        <rank>3</rank>
> >    </node>
> >    <node>
> >        <rank>2</rank>
> >    </node>
> >    <node>
> >        <rank>1</rank>
> >    </node>
> ></node>
> ></input>
> >
> >I need to reorganise the nodes so that they are organised in number 
> >order down the nodes within their tree, so the output should be like 
> >this: <output> <node>
> >    <rank>1</rank>
> >    <node>
> >        <rank>7</rank>
> >    </node>
> >    <node>
> >        <rank>66</rank>
> >    </node>
> >    <node>
> >        <rank>88</rank>
> >    </node>
> ></node>
> ><node>
> >    <rank>2</rank>
> >    <node>
> >        <rank>1</rank>
> >    </node>
> >    <node>
> >        <rank>2</rank>
> >    </node>
> >    <node>
> >        <rank>3</rank>
> >    </node>
> ></node>
> ></output>
> >I can sort one level by using the code below, but I'm 
> struggling to find a
> >way to re-order the second level within the first level (and 
> the third level
> >later).
> >
> ><xsl:template match="/input">
> >  <xsl:call-template name="ascending-numeric-sort-l1">
> >    <xsl:with-param name="seqnuml1" select="node/rank"/>
> >  </xsl:call-template>
> >
> ></xsl:template>
> >
> ><xsl:template name="ascending-numeric-sort-l1">
> >  <xsl:param name="seqnuml1"/>
> >  <xsl:for-each select="$seqnuml1">
> >    <xsl:sort select="." data-type="number" order="ascending"/>
> >    <xsl:copy-of select="parent::node()"/>
> >  </xsl:for-each>
> ></xsl:template>
> >
> >Can anybody offer any advice please?
> >Thanks
> >Chris
> >
> > XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> >
> >  
> >
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list