That did it!

Thanks!

And I did that search on google... Wow...  

I can see I still have soooo much to learn.

Chris


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> 
> this is a grouping problem (ask google for muenchian 
> grouping) assuming you want to distinguish on all those child 
> elements and attributes, and none of them have a : character 
> (any character you can use as a separator) then first build a key:
> 
> <xsl:key name="x" match="item" use=" 
> concat(name,':',type,':',carried,':',cost/@name,':',cost/@valu
> e,':',weight)"/>
> 
> now step through all the items, just taking the first with 
> each key value
> 
> <xsl:for-each select="items/item[ generate-id(.)=generate-id(key('x',
> concat(name,':',type,':',carried,':',cost/@name,':',cost@value
> ,':',weight))[1])]">
> <xsl:copy-of select="."/>
> or whatever else you want to do with these items </xsl:for-each>
> 
> Not tested
> 
> David
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 
> 



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list