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Hi :)
The following works, but I suspect there is a much simpler way. <xsl:template match="textdata[@fileref]">
<xsl:variable name="dir_abs"
select="replace(base-uri(/),'[^\/]+$','')"/>
<!--
AFAICS, basically resolve-uri()
concatenates if @fileref is relative, and
leaves unchanged if it's absolute
-->
<xsl:variable name="file_abs"
select="resolve-uri(@fileref,$dir_abs)"/>
<xsl:copy-of select="unparsed-text($file_abs,'utf-8')"/>
</xsl:template><xsl:template match="textobject[textdata[@fileref]]"> <xsl:apply-templates/> </xsl:template> How could I get the base dir of the input ($dir_abs), directly, without doing replace()? Tobi -- http://www.pinkjuice.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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