Subject: Re: sorting question
From: "Margarit A. Nickolov" <man@xxxxxxxxxxxxxxx>
Date: Wed, 28 May 2003 12:35:41 +0300
|
lars_huttar@xxxxxxx said:
> select="/*/sd:Service[sd:ServiceDescription/@ServiceName='Y'
> and ../sd:Service[sd:ServiceID < current()/sd:ServiceID]]"
it works.
> But even if this worked, I don't think this would really be a win because it
> could be much less efficient (order N*N) than your original approach (order N
> * log N for sorting).
I do not pursue any performance, just learning XSLT.
> Don't think I helped much but nobody else had replied.
Thanks a lot, it helped me.
best regards, margarit nickolov.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|