[xsl] obtaining name of output file

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Subject: obtaining name of output file
From: "Daniel Brauer" <daniel.brauer@xxxxxxxxxxxxx>
Date: Wed, 7 May 2003 16:50:32 +0200

Hi,

I need to obtain the name of the output file as specified at the command
line of the XSLT-processor.
Is there a way to do this?

Thanks
Daniel.




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
obtaining name of output file Daniel Brauer - Wed, 7 May 2003 10:49:02 -0400 (EDT) <= David Carlisle - Wed, 7 May 2003 11:27:16 -0400 (EDT) Gary Cornelius - Wed, 7 May 2003 12:59:28 -0400 (EDT) Michael Kay - Wed, 7 May 2003 15:57:34 -0400 (EDT) <Possible follow-ups> Sundar Shanmugasundaram - Wed, 7 May 2003 11:12:12 -0400 (EDT)

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RE: Matching a series of elem, Doug Howell (IT)	Thread	Re: obtaining name of output , David Carlisle
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