hi expert,
sorry for the syntax error

<record>
<row year="2001" month="1"/>
<row year="2001" month="2"/>
<row year="2001" month="3"/>
<row year="2001" month="4"/>
<row year="2002" month="1"/>
<row year="2002" month="2"/>
<row year="2002" month="3"/>
<row year="2003" month="1"/>
<row year="2003" month="2"/>

</record>

From: "Cheung Tin Po" <timothy298@xxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
CC: timothy298@xxxxxxxxxxx
Subject:  Show YEAR once if the YEAR same as preious element  by xsl
Date: Sun, 27 Apr 2003 03:57:44 +0000

hi expert,

i get the following XML file

<record>
<row year="2001" month="1">
<row year="2001" month="2">
<row year="2001" month="3">
<row year="2001" month="4">
<row year="2002" month="1">
<row year="2002" month="2">
<row year="2002" month="3">
<row year="2003" month="1">
<row year="2003" month="2">
</record>

i want to transform it to html with the following result

2001/1
    2
    3
    4
2002/1
    2
    3
2003/1
    2

as XSLT cannot store the variable so i cannot think any method to should the result.

:<
From Timothy

_________________________________________________________________
No masks required! Use MSN Messenger to chat with friends and family. http://go.msnserver.com/HK/25382.asp


XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list