"John Chen" <jchen@xxxxxxxxxxxx> wrote in message
news:5.0.2.1.0.20030304115132.00b604e0@xxxxxxxxxxxxxxxxxxxx
> I would like to create an XSL that takes an XML file and returns it as its
> output. Is that easy to do?

Yes, use:

<xsl:copy-of select="/"/>

A lot more useful (because it can be overridden) is the following template,
known as the "identity transformation":
http://www.w3.org/TR/xslt#copying

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL




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