Subject: Re: outputing tags
From: Sam Carleton <sam@xxxxxxxxxxxxxx>
Date: Mon, 6 Jan 2003 11:42:54 -0500
|
On Mon, Jan 06, 2003 at 11:30:47AM -0500, Passin, Tom wrote:
> [ Sam Carleton]
>
> > Ok, then how do I do this: I have my xml file with all the
> > info I need in it. There is one element named <quote> which
> > contains quotes. Some quotes need to have line break (
> > <br>'s in HTML). How do I denote a line break in the XML and
> > then how do I transform it?
> >
>
> It is all a matter of what you start with and what you want to end up
> with. The stylesheet transforms the one into the other.
>
> So what do you want to end up with? You say you want a "line break" in
> the XML, but XML inherently knows nothing about line breaks. Perhaps
> you mean that you want to create html output that happens to be
> well-formed xml as well? Then a <br/> element would just stay as is, if
> there is one in the source. Otherwise, no one can answer you without
> knowing how to determine where line breaks should occur.
You are correct, I want the ,br/> in the html.
> In general, if you just want to echo some existing element content
> (complete with <br/> or other elements), you would use xsl:copy-of. If
> you want to echo an element but change some of its child elements, use
> an identity transform where you specify templates only for the elements
> you want to change. The FAQs and archives contain examples.
so that is what xsl:copy-of is for, I will look into that!
Thanks a millon!
Sam
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|