Hi,

Would 
 
 <xsl:if test="parent::view and not(parent::view/following-sibling::view)">

be what you are after?

cheers
andrew



> -----Original Message-----
> From: jfi@xxxxxxxxxxxxxxxx [mailto:jfi@xxxxxxxxxxxxxxxx]
> Sent: 08 January 2003 15:43
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  position() and last() problem
> 
> 
> 
> Hi List,
> 
> I´ve got a problem finding out whether a parent element is a 
> "last()" one.
> I read the FAQ but it didn´t help.
> 
> My XML file has the following structure:
> 
> <views>
>   <view>
>     <stuff>...</stuff>
>   </view>
>   <view>
>     <stuff>...</stuff>
>     <view>
>       <stuff>...</stuff>
>       <view>
>         <stuff>...</stuff>
>       </view>
>        <view>
>         <stuff>...</stuff>
>       </view>
>     </view>
>     <view>
>       <stuff>...</stuff>
>     </view>
>   </view>
> </views>
> 
> That means each <view>-element can contain an undefined 
> number of other
> <view>s. What I want to know is whether the parent of a 
> <view> - if it is
> also the view - is the last one.
> 
> I tried <xsl:if test="ancestor::con:view[1][position()]!=last()">, but
> understanding more and more of XSLT I know that can´t work. 
> But I don´t
> know yet what can.
> All whitespace is stripped.
> 
> Thanks for your help!
> 
> Julia
> 
> 
> 
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 
> 
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