Subject: Re: outputing tags
From: Sam Carleton <sam@xxxxxxxxxxxxxx>
Date: Sat, 4 Jan 2003 20:36:35 -0500
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On Sat, Jan 04, 2003 at 06:43:46PM -0500, cknell@xxxxxxxxxx
wrote:
> The XML sample you listed, is it the source which you are
> trying to transform, or is the the output you desire to
> receive? In either case, send us a sample of the other and
> it will be easier to help.
Sorry about that. The XML is the source. I would like the
output to look something like this:
<b>This is to be displayed<br/>This is a new line<br/>And this
is on a third line</b>
Someone else posted with the obvious correct answer. I
thought I had tried it, but guess I hadn't.
> Rap yourself on the knuckles with a ruler! We do not output
> tags, we output a node tree comprised of elements (which are
> bounded by opening and closing tags).
Ok, then how do I do this: I have my xml file with all the
info I need in it. There is one element named <quote> which
contains quotes. Some quotes need to have line break ( <br>'s
in HTML). How do I denote a line break in the XML and then
how do I transform it?
Sam
> -----Original Message-----
> From: Sam Carleton <sam@xxxxxxxxxxxxxx>
> Sent: Sat, 4 Jan 2003 14:35:39 -0500
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject: outputing tags
>
> Folks,
>
> How do I output some tags? The xml looks like this:
>
> <sometag>This is to be displayed<br/>This is a new
> line<br/>And this is on a thrid line</sometag>
>
> Then I have a template like this:
>
> <xsl:template match="sometag">
> <b><xsl:apply-templates/></b>
> </xsl:template>
>
> How do I write a template that will output both of the
> <br/>'s? so that it is displayed the right way?
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| Current Thread |
- outputing tags
- Sam Carleton - Sat, 4 Jan 2003 14:35:09 -0500 (EST)
- <Possible follow-ups>
- Chandra - - Sat, 4 Jan 2003 15:11:16 -0500 (EST)
- cknell - Sat, 4 Jan 2003 18:43:41 -0500 (EST)
- Sam Carleton - Sat, 4 Jan 2003 20:36:06 -0500 (EST) <=
- cknell - Sun, 5 Jan 2003 11:34:04 -0500 (EST)
- Edward . Middleton - Mon, 6 Jan 2003 05:29:14 -0500 (EST)
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