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Hi George, There must be a better way to test if the current node is an attribute node, but the best I can think of is this: <xsl:if test="../@*/."> or <xsl:if test="parent::node()/attribute::node()/self::node()"> Regards, Tom SW XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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