Subject: Re: xsl filter problem
From: Dimitre Novatchev <dnovatchev@xxxxxxxxx>
Date: Thu, 26 Dec 2002 03:44:29 -0800 (PST)
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Hi Yuval,
> When choosing "all cities" - the result is an empty table instead of
> the list of all cities with the customers names.
> I tried to giva the param "city" a diect value of "*" or " '*' " and
> it still didn't work.
> How can I pass a value to this param which will act like : <xsl:for-
> each select="customers/customer[city=*]"> ??
Use:
customers/customer[city=$city or $city = '*']
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
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- xsl filter problem
- Yuval - Wed, 25 Dec 2002 18:50:02 -0500 (EST)
- Mike Brown - Wed, 25 Dec 2002 19:59:21 -0500 (EST)
- Yuval - Thu, 26 Dec 2002 05:10:00 -0500 (EST)
- Mike Brown - Thu, 26 Dec 2002 06:05:23 -0500 (EST)
- <Possible follow-ups>
- Dimitre Novatchev - Thu, 26 Dec 2002 06:44:53 -0500 (EST) <=
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