Subject: RE: a*b, sum(c*d), sorted on <sort>
From: "Andrew Welch" <awelch@xxxxxxxxxxxxxxx>
Date: Wed, 4 Dec 2002 16:30:18 -0000
|
I would use a use a temporay tree containing a sorted list of <item>
with the first part of the calculations complete, so you would have
something like:
<root>
<item><a*b>20</a*b><sumCD>18</sumCD></item>
<item><a*b>6</a*b><sumCD>40</sumCD></item>
....
Then produce your table by applying-templates to the temporary tree,
using sum() on the <sumCD> element to get the cumulative column.
cheers
andrew
> Here is my XML:
>
> <root>
> <item><a>1</a><b>2</b><c>2</c><d>7</d><sort>3</sort></item>
> <item><a>2</a><b>3</b><c>5</c><d>8</d><sort>2</sort></item>
> <item><a>3</a><b>4</b><c>1</c><d>2</d><sort>4</sort></item>
> <item><a>4</a><b>5</b><c>2</c><d>9</d><sort>1</sort></item>
> </root>
>
> For each <item> I need to produce a row containing
> cells for a*b and cumulative c*d where the items
> are taken sorted on <sort>:
>
> +-----+----------+
> | a*b | sum(c*d) |
> +-----+----------+
> | 20 | 18 |
> +-----+----------+
> | 6 | 58 |
> +-----+----------+
> | 2 | 72 |
> +-----+----------+
> | 12 | 74 |
> +-----+----------+
>
> The above a gross simplification, but I would like to get input from
> people on how they would structure the problem as it has a lot
> more detail in reality. In a nutshell, I have both recursive and
> non-recursive calculations to perform in each row.
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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