With Saxon version 7.2, I am trying to apply a stylesheet to a stylesheet.
Is there any way to exclude the aliased namespace prefix from the output?

In the sample below I am trying to get rid of the output line:
  xmlns:x="http://www.w3.org/1999/XSL/Transform" 

Sample source stylesheet:

<?xml version="1.0"?>
<xsl:stylesheet version="2.0"
  xmlns:xsl  = "http://www.w3.org/1999/XSL/Transform">
</xsl:stylesheet>

Sample stylesheet to apply to the source stylesheet:

<?xml version="1.0"?>
<xsl:stylesheet version="2.0"
  xmlns:xsl  = "http://www.w3.org/1999/XSL/Transform"
  xmlns:x    = "http://www.w3.org/1999/XSL/TransformAlias"
  exclude-result-prefixes="x">
  <xsl:namespace-alias stylesheet-prefix="x" result-prefix="xsl"/>
  <xsl:template match="/">
    <xsl:copy>
      <x:stylesheet>
        <x:template m="/"><x:value-of select="test"/></x:template>
      </x:stylesheet>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

Output produced:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
  xmlns:x="http://www.w3.org/1999/XSL/Transform" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template m="/"><xsl:value-of select="test"/></xsl:template>
</xsl:stylesheet>

Output disired:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template m="/"><xsl:value-of select="test"/></xsl:template>
</xsl:stylesheet>



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list