Subject: Re: XPath expression for finding out the depth of a given node?
From: Peter Davis <pdavis152@xxxxxxxxx>
Date: Sun, 17 Nov 2002 12:25:07 -0800
|
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1
On Sunday 17 November 2002 12:10, Peter Davis wrote:
> count(ancestor-or-self::*)
On second thought, you would need to change that to
count(ancestor-or-self::node()), to be consistant with text() and other
nodes. Or, you could just do count(ancestor::*)+1. Hope you get the idea.
- --
Peter Davis
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.0.7 (GNU/Linux)
iD8DBQE91/sjhDAgUT1yirARAnXbAJ9Zm0xchJCMmJfZ/c3k2IjRhIGMjgCfVXBf
HhmhMpmq/EF16s0ZgvR1euU=
=fBCl
-----END PGP SIGNATURE-----
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
Cart
