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Saurabh,
At 08:35 AM 11/13/2002, you wrote: Can xsl:document funtion take (e:\base\*.xml)as input? If you're asking whether the expression document('e:\base\*.xml') will work, the answer is no, since the string argument violates URI syntax. If you're asking whether document('*.xml') works, it's still no, for the same reason. XSLT really doesn't want to specify a language for traversing a file system, so it uses URI syntax; URIs don't use wildcards. However, the document() can take a node set argument, so you can do document(file) in a context where your source has children <file>one.xml</file> <file>two.xml</file> <file>three.xml</file> and get them all that way. Of course, it may be convenient to put the file list somewhere other than your source document. In which case, naturally, you retrieve the node set with a document() function. As in: <xsl:variable name="filenames" select="document('filelist.xml')//file"/> and then call document($filenames), and voila. I hope that helps, Wendell
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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