Subject: About <xsl:param> and <xsl:with-param>
From: Hélder Sousa <hsousa@xxxxxx>
Date: Tue, 5 Nov 2002 11:54:41 -0000
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Hi..
In the next xsl I want to make that the param "cod" be incremented in each time that the <xsl:for-each> cicle occurs, but it's result is an error:
"javax.xml.transform.TransformerException: xsl:with-param is not allowed in this position in the stylesheet!"
Why?!
Tks
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns:xalan="http://xml.apache.org/xslt">
<xsl:param name="cod">0</xsl:param>
<xsl:output method="html"/>
<xsl:template match="/">
<xsl:for-each select=".//Boy">
<xsl:with-param name="cod" select="number($cod+1)"/>
<!--make other things-->
</xsl:for-each>
</xsl:template>
</xsl:transform>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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