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Jan Krattiger wrote:
i use xsl:sort to sort the output. now i need something like xsl:number to give the elements numbers from 1-n, but i need the sorted one to be numbered. xsl:number uses the unsorted, "original" xml to number. one possiblity would be sorting the xml before transforming... but that not possible in my case.. Well, temporary tree aka result tree fragment? That's obviously not a very effective, but at least simple and clear solution - first sort to the variable, then convert it to a nodeset and process using xsl:number. -- Oleg Tkachenko eXperanto team Multiconn Technologies, Israel XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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