just use the ancestor::* axis

<xsl:for-each select="ancestor::*">
  <xsl:value-of select="name()"/>
</xsl:for-each/>

I bet you are kicking yourself...

cheers
andrew

> -----Original Message-----
> From: jm3 [mailto:lists@xxxxxxx]
> Sent: 23 October 2002 15:22
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  backwards tree-traversal algorithm?
> 
> 
> hello, having some trouble making this work: within my stylesheet,
> i have selected a node somewhere in the midst of the document tree,
> several nested elements deep.  what i would like to do is, given
> this node N (at arbitrary depth), walk *back* up the document tree
> hierarchy, element by element, printing the successive parent elements
> (technically, printing each element's "name" @ribute).
> 
> so with node N being <c> and the following document:
> 
> <root>
>   <a>
> 	  <b>
> 		  <c/>
> 		</b>
> 		<d/>
> 		<e/>
> 	</a>
> </root>
> 
> i want to print: b, a, root.
> 
> my pseudocode was along the lines of:
> 
> current = node
> while current != root
>   current = ../
> 	print current/@name
> 
> seems simple.
> 
> recursive templates seemed like the way to do this in xsl, but i
> can't get this to do anything, apparently because the processor i'm
> using (sablotron 0.90) won't let me use XPath on the node set i am
> passing with call-template (as a param) because it's "not a node-set".
> 
> so i guess i have two questions:
> 
> 1. what is the best algorithm/approach to walk back up the 
> parent:: tree, printing each element?
> 
> 2. does sabcmd not have a node-set() function? is this what's 
> stopping me?
> 
> (if it helps, the stylesheet will know what depth level the current
> node is at, and the unique @name attribute of each parent element.)
> 
>  jm3 / john manoogian III / http://jm3.net / jm3@xxxxxxx 
> 
>         > > > http://jm3.net/linkworld < < <
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
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