<xsl:template match="/db/*">
   <xsl:copy>
      <xsl:copy-of select="@*"/>
      <xsl:attribute name="newattribute">newAttributeValue</xsl:attribute>
   </xsl:copy>
</xsl:template>

On Tue, 15 Oct 2002, Jeni Tennison wrote:

Try copying the existing attributes with xsl:copy-of. Something like:

<xsl:template match="name">
 <name number="20">
   <xsl:copy-of select="@*" />
 </name>
</xsl:template>

Thanks.  However, can this solution be used if I do not know the
element name (in this case, `name') a-priori?

For example, if I'd like to do this in:

<xsl:template match="/db/*">
   ...
</xsl:template>

Best,

S. Perugini

System Development
VIRBUS AG
Fon  +49(0)341-979-7419
Fax  +49(0)341-979-7409
joerg.heinicke@xxxxxxxxx
www.virbus.de