Re: [xsl] Getting the XPath of a node

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Subject: Re: Getting the XPath of a node
From: Peter Davis <pdavis152@xxxxxxxxx> (by way of Peter Davis <pdavis152@xxxxxxxxx>)
Date: Wed, 4 Sep 2002 02:46:23 -0700

On Wednesday 04 September 2002 02:44, you wrote:
> reverse document order

I'm an idiot, please ignore that.  You can use <xsl:for-each
select="ancestor-or-self::*>, as Mike Brown said, instead of my stupid
recursive template.

--
Peter Davis


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
RE: Getting the XPath of a node Jarno . Elovirta - Wed, 4 Sep 2002 05:23:04 -0400 (EDT) <Possible follow-ups> Peter Davis - Wed, 4 Sep 2002 05:45:23 -0400 (EDT) <= Macaulay,Malcolm (US) - Wed, 4 Sep 2002 15:15:34 -0400 (EDT) Dennis - Thu, 5 Sep 2002 07:46:20 -0400 (EDT) Dennis - Mon, 9 Sep 2002 08:36:38 -0400 (EDT)

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RE: Getting the XPath of a no, Jarno . Elovirta	Thread	RE: Getting the XPath of a no, Macaulay,Malcolm (US
Re: Getting the XPath of a no, Peter Davis	Date	Re: Getting the XPath of a no, Dimitre Novatchev
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