> Mike> It all gets easier in XPath 2.0, where you can write
> Mike>
> Mike> <xsl:if test="every $x in preceding-sibling::*
> Mike> satisfies name($x) != name(.)">
>
> Are you _sure_ that's easier than
>
> <xsl:if test="preceding-sibling::*[name(.)=name(current())]">
>
Well, I can't say it's a simpler solution; but in my case, this
afternoon, it was a solution that I found more easily.
Michael Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
|---|
|
Laura Jenkins - Wed, 11 Sep 2002 10:08:19 -0400 (EDT)
Stuart Brown - Wed, 11 Sep 2002 10:55:33 -0400 (EDT)
scruss - Wed, 11 Sep 2002 10:56:52 -0400 (EDT)
|
|
Cart
