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Hi all,
could anyone tell me how I can pass a parameter to a stylesheet from PHP 4.2.1 i.e. from file_name.php to file_name.xsl? Thanks, Anna _________________________________________________________________ Join the world?s largest e-mail service with MSN Hotmail. http://www.hotmail.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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