Hi Jem!

Your problem already have been resolved (see Jeni, Stuart and Morrow's
replies) and they work with your example, but, has Stuart said, it only
work with the first <record type="continue">.

with a little change on Jeni's template it could work on every
following-sibling <record type="continue">.

heres is the xsl:

 <xsl:template match="records">
  <xsl:apply-templates select="record[@type = 'normal']" />
 </xsl:template>

 <xsl:template match="record[@type = 'normal']">
  <record>
   <xsl:copy-of select="*" />
   <xsl:apply-templates select="following-sibling::record[1][@type =
'continuation']"/>
  </record>
 </xsl:template>

 <xsl:template match="record[@type = 'continuation']">
  <xsl:copy-of select="*" />
  <xsl:apply-templates select="following-sibling::record[1][@type =
'continuation']"/>
 </xsl:template>

hope that this helps you


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Jem Clear
Sent: Tuesday, August 20, 2002 10:42 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  How to output partial elements?


I have been bashing my brain for days over this and I need help. Here is
the (style of) input I have:

  <record n="1" type="normal">
    <foo> <x>... <y>...</y> ...</x> </foo>
    <bar> <things> ... </things> </bar>
  </record>
  <record n="2" type="normal">
    <foo> <x>... <y>...</y> ...</x> </foo>
  </record>
  <record n="3" type="continuation">
    <bar> <things> ... </things> </bar>
  </record>
  <record n="4" type="normal">
    <foo> <x>... <y>...</y> ...</x> </foo>
    <bar> <things> ... </things> </bar>
  </record>

The problem is <record>s 2 and 3: they need to be concatenated. (The 'n'
attribute is irrelevant: I only put it there for easy reference in
illustration.)

At first I thought this was easy:

   have a template to match <record>
   if (@type != "continuation") {
     write "</record>" to the output
   }
   write "<record>" to output
   copy all child nodes to output

But XSLT won't allow partial (malformed) XML to be written to the output
tree from a <xsl:template> -- so I can't do this!
*Everyone* tells me XSLT is "the right tool" for this sort of task: but
if I'd followed my natural inclination and hacked it up in Perl it'd be
trivial to chop the offending two lines out! :)

Any ideas how to make the output look like this:

  <record type="normal">
    <foo> <x>... <y>...</y> ...</x> </foo>
    <bar> <things> ... </things> </bar>
  </record>
  <record type="normal">
    <foo> <x>... <y>...</y> ...</x> </foo>
    <bar> <things> ... </things> </bar>
  </record>
  <record type="normal">
    <foo> <x>... <y>...</y> ...</x> </foo>
    <bar> <things> ... </things> </bar>
  </record>

Thanks

Jem Clear
29 School Road, Moseley, Birmingham, B13 9TF, UK
Tel & Fax: +44 (0)121 689 3637
Email:     jem@xxxxxxxxxxxxxx


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list