Interesting,
Could you show me?  I couldn't see a way of getting
a sorted nodeset into a variable. Wouldn't this approach
require that?

-- Mike Berrow

----- Original Message ----- 
From: "Mike Brown" <mike@xxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, August 08, 2002 10:09 PM
Subject: Re:  sort / unsort


Mike Berrow wrote:
> Does anyone see a better way?

I was going to try the Kay/Becker/Holman technique from the FAQ.
  http://www.dpawson.co.uk/xsl/sect2/muench.html#d197e74

That is, find the difference between all the nodes and the sorted
nodes to get the remaining nodes. No need for generate-id(); count()
and != ought to work nicely.

   - Mike
____________________________________________________________________________
  mike j. brown                   |  xml/xslt: http://skew.org/xml/
  denver/boulder, colorado, usa   |  resume: http://skew.org/~mike/resume/

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