Hi all,

I'm stuck. I'm sure this is very simple, but I've been searching my XSL
books and the web and can't find an answer.

Here's my original XSL, in which I select and sort based on the S3G
attribute of the <record>.

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

<xsl:output method="html"/>

<xsl:template match="/">
<TABLE border="1" width="90%" style="font-size:10pt" cellpadding="0"
cellspacing="0">
<tr valign="top">
  <th width="16%"><b>Field Name</b></th>
  <th width="42%"><b>Description</b></th>
  <th width="42%"><b>Entry Detail</b></th>
</tr>
<xsl:for-each select="//brpfields/record[@S3G >'0']">
<xsl:sort data-type="number" select="@S3G"/>
etc. etc.



I want to use a parameter in place of S3G (Ultimately I'll be passing the
value from an external javascript).  So I tried this:
 
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:param name="param1" select="S3G"/>

<xsl:output method="html"/>

<xsl:template match="/">
<TABLE border="1" width="90%" style="font-size:10pt" cellpadding="0"
cellspacing="0">
<tr valign="top">
  <th width="16%"><b>Field Name</b></th>
  <th width="42%"><b>Description</b></th>
  <th width="42%"><b>Entry Detail</b></th>
</tr>
<xsl:for-each select="//brpfields/record[@$param1 >'0']">
<xsl:sort data-type="number" select="@$param1"/>

But the transformation chokes on the $.  I've tried various permutations of
quotes; I've tried braces; I've tried everything I can think of.  Why
doesn't it like the parameter for the <record> attribute value?

Many thanks!

Kathryn

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