Subject: Re: getting distinct content from list (?)
From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx>
Date: Thu, 22 Aug 2002 15:36:59 +0000
|
Kurt,
Your Problem is simple but without you providing the XML file, nothing much
can be done.can you please send a snip.. of your xml so that its easu to
sort your problem.
Vasu
From: Kurt George Gjerde <kurt.gjerde@xxxxxxxxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: getting distinct content from list (?)
Date: Thu, 22 Aug 2002 16:31:10 +0200 (MET DST)
Hi,
The least of my xslt problems at the moment is this one (I have others
which I'm sure I'll come back to ;). This is probably easy
but I just can't see it. Here it goes.
I have an xpath which results in a list like:
'cynthia', 'bob', 'janet', 'bob', 'jack', 'bob', 'jack'.
These are user IDs collected from different locations in a document. The
actual xpath is:
notify/@user |
/ming/users/user[@global-notify='yes']/@id |
/ming/client[@id=$myClient]/admin/@user
I need to output this as: "bob, cynthia, jack and janet".
Without the duplicates (sorted and xslt 1.0).
How?
Thanks,
-Kurt.
__________
kurt george gjerde <kurt.gjerde@xxxxxxxxxxxxxxxxx>
intermedia uib, university of bergen
Free Jon - http://www.efn.no/freejon01-2002.html
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
_________________________________________________________________
MSN Photos is the easiest way to share and print your photos:
http://photos.msn.com/support/worldwide.aspx
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|