Hi.
You could use PERSON/@*[not(name()='NAME')]
Hope that this help you.

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Daniel N.
Javastark
Sent: Tuesday, July 16, 2002 10:36 AM
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject:  the OTHER attributes with XPath


Hi, I'm trying to pull off all the OTHER attributes than one with a
particular name from, for example, this xml snippet:

<PERSON NAME="JUAN LUIS" UNIQUEID="A" HEIGHT_CATEGORY="2" SEX="M">

Let's say I want to get all the attributes except for "NAME":
"UNIQUEID", "HEIGHT_CATEGORY", and "SEX".

I can pull off the "PERSON" node which contains an attribute named
"NAME":

	xpath: //PERSON[name(@NAME)='NAME']

or any "PERSON" node that does NOT contain the attribute "NAME":

	xpath: //PERSON[not(name(@NAME)='NAME')]

or all the attributes of "PERSON":

	xpath: //PERSON/@*

but I don't know how to get all the attributes except "NAME".

Is there any way to do this?  In XSL using or programatically I can do
it by iterating through the attributes, of course, but if there's a way
to do it with XPath, great.

Thanks,
Dan



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list