Subject: <xsl:for-each> help
From: "Zoe" <zoe@xxxxxxxxxxxx>
Date: Wed, 1 May 2002 15:56:11 -0400
|
Hi,
I want to display the specific service id="01"'s name.
how can I approach this? The result will be 'My News'.
does it have any condition that I can use? Thanks.
<xsl:for-each select="dynamictree/category/service"....? >
<!-- serviceid =01, name="My News" -->
</xsl:for-each>
XML file:
- <dynamictree version="1" statuscode="0" statusdesc="OK">
- <category id="1" name="Favorite">
- <service id="01" name="My News">
<querykeyword id="7003" name="News USA" />
<querykeyword id="7004" name="News Africa" />
</service>
- <service id="02" name="My Stocks">
<querykeyword id="7001" name="Stock Quotes" />
</service>
</category>
</dynamictree>
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- <xsl:for-each> help
- Zoe - Wed, 1 May 2002 15:57:43 -0400 (EDT) <=
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- Zoe Peng - Wed, 1 May 2002 17:19:04 -0400 (EDT)
- Zoe Peng - Wed, 1 May 2002 18:51:11 -0400 (EDT)
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