Subject: Re: xsl:call-template name="$tempname"
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Sat, 25 May 2002 00:38:05 +0200
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Hello Ming,
It's not possible. One thing you can do:
<xsl:when test="$tempname = 'foo'">
<xsl:call-template name="foo"/>
</xsl:when>
<xsl:when test="$tempname = 'bar'">
<xsl:call-template name="bar"/>
</xsl:when>
The other thing is to create your stylesheet by a transformation.
Joerg
Ming wrote:
Hi,
I'm trying to use a variable as the xsl:call-template' name value as:
<xsl:call-template name='$tempname'>
....
</xsl:call-template>
But the compile gave me error saying that it cannot find template $tempname
which means it doesn't see $tempname as a variable but a string.
Do you have any idea how I can do this?
Thanks a lot in advance.
Ming
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- Ming - Fri, 24 May 2002 14:38:54 -0400 (EDT)
- E L - Fri, 24 May 2002 15:12:40 -0400 (EDT)
- Ming - Fri, 24 May 2002 18:39:27 -0400 (EDT)
- Joerg Heinicke - Fri, 24 May 2002 18:48:30 -0400 (EDT) <=
- Ming - Fri, 24 May 2002 18:59:19 -0400 (EDT)
- David Carlisle - Sat, 25 May 2002 13:08:12 -0400 (EDT)
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