Subject: Re: Parsing a List
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Tue, 21 May 2002 22:00:11 +0200
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Hello Kenneth,
you can pass parameters to the stylesheet. In your case for example the
number of the first element to show in the list:
<xsl:param name="first" select="1"/>
<xsl:param name="count" select="50"/>
> <xsl:template match="DATALIST">
> <table cellpadding="5" cellspacing="0" border="0">
> <tr>
> <td width="135"><u><font color="green">Company</font></u></td>
> <td width="330"><u><font color="green">Address </font></u></td>
> <td width="100"><u><font color="green">Phone </font></u></td>
> <td width="100"></td>
> </tr>
> <xsl:apply-templates select="customer"/>
changed to:
<xsl:apply-templates select="customer[position() >= $first][position()
<= $count]"/>
> </table>
> </xsl:template>
<xsl:template match="customer">
<tr>
<td valign="top"><a><xsl:attribute name="href">
adminViewCompanyByID?companyid=<xsl:value-of select="id"/>&companyname
=<xsl:value-of select="invoicename"/></xsl:attribute><xsl:value-of select="
invoicename"/></a></td>
<td valign="top"><xsl:value-of select="invoiceaddress"/></td>
<td valign="top"><xsl:value-of select="phone"/></td>
</tr>
</xsl:template>
Simply, all this code does is displays all customers contained in the
database. However my problem is that I have 1000s of customers in the
database and as a result all these are returned in one huge list. My web
page is therefore ridicously wrong.
Does anyone know anyway of displaying say 50 Customers at a time with a
'next' and "previous" link to display the next or previous 50.
Any help would be greatly appreciated.
Thanks
- ken
Regards,
Joerg
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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