Try this:

XML:

<?xml version="1.0" encoding="UTF-8"?>
<Books>
	<book>
		<price>20</price>
	</book>
	<book>
		<price>10</price>
	</book>
	<book>
		<price>5</price>
	</book>
	<book>
		<price>100</price>
	</book>
</Books>

XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:template match="/">
		<xsl:value-of select="/Books/book[not(price &gt; ../book/price)]/price"/>
	</xsl:template>
</xsl:stylesheet>

cheers

Malcolm



-----Original Message-----
From: tinku [mailto:amegha1@xxxxxxxxxxxxxx]
Sent: 04 May 2002 18:15
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Finding the lowest 'price' element


Hi all,

    I have several book elements, in which each book element has a 
'price' child element.

   <book>
     <price>20</price>
   </book>
   <book>
     <price>10</price>
   </book>
     .
     .
     .

Now, I need to find the lowest 'price' element using XSLT?

One solution which i think is:

    1. first sort the above xml document using <xsl:sort>

    2. Now we get a new tree with all the price elements in 
ascending order.

    3. Now we will find the first 'price' element which is the 
lowest using the "position()" function.

   Here the result tree is again fed with a new stylesheet(to find 
the first position), to the xslt processor.

Is there any better solution than this?

Thanks in advance!!
_________________________________________________________
Click below to visit monsterindia.com and review jobs in India or 
Abroad
http://monsterindia.rediff.com/jobs


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list