Subject: Re: XSLT test on the name of a node
From: Jörg Heinicke <joerg.heinicke@xxxxxx>
Date: Mon, 25 Mar 2002 07:02:24 +0100
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> <xsl:variable name="translation" select="$language/node()[local-name() =
@ld-tag]" />
Hello Tim,
I think the problem is in the above code. You are selecting nodes, whose
local name is the same as the value of their ld-tag attribute. What you
probably want to have is current()/@ld-tag:
<xsl:variable name="translation" select="$language/node()[local-name() =
current()/@ld-tag]" />
Furthermore node() is a superset of *. node() = * + text() + comment() +
processing-instruction().
Regards,
Joerg
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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