[Home] [By Thread] [By Date] [Recent Entries]

Subject: Re: Contains(@href. '/') returns false
From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>
Date: Fri, 8 Mar 2002 12:39:32 +0000
Hi Nilesh,

You've forgotten some quotes in your call:

> <xsl:call-template name="lastIndexOf">
>   <xsl:with-param name="string" select="substring-before(@href, '#')" />
>   <xsl:with-param name="char" select="/" />
> </xsl:call-template>

should be:

  <xsl:call-template name="lastIndexOf">
    <xsl:with-param name="string" select="substring-before(@href, '#')" />
    <xsl:with-param name="char" select="'/'" />
  </xsl:call-template>

otherwise you're passing the value of the root node as the $char
parameter.
  
Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member