Subject: Re: Contains(@href. '/') returns false
From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>
Date: Fri, 8 Mar 2002 12:39:32 +0000
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Hi Nilesh,
You've forgotten some quotes in your call:
> <xsl:call-template name="lastIndexOf">
> <xsl:with-param name="string" select="substring-before(@href, '#')" />
> <xsl:with-param name="char" select="/" />
> </xsl:call-template>
should be:
<xsl:call-template name="lastIndexOf">
<xsl:with-param name="string" select="substring-before(@href, '#')" />
<xsl:with-param name="char" select="'/'" />
</xsl:call-template>
otherwise you're passing the value of the root node as the $char
parameter.
Cheers,
Jeni
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Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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