----- Original Message -----
From: "XSL Developer" <vsd18@xxxxxxxxxxxxxx>


>
> dear xsl members,
> i have a problem. here it goes..
> xml structure:
>
> <root>
> <schedule category="title" type = "title2">
> title2
> </schedule>
> <schedule category="title" type = " title1">
> title1
> </schedule>
> <schedule category="title" type = "title3">
> episode
> </schedule>
> <schedule category="description" type="desc1">
> desc1
> </schedule>
> </root>

this should  do the trick, though i havent tested.

xml file
----------------------------------------
<?xml version="1.0" ?>
<root>

<schedule category="title" type="title2">
title2
</schedule>

<schedule category="title" type="title1">
title1
</schedule>

<schedule category="title" type="title3">
episode
</schedule>

<schedule category="description" type="desc1">
desc1
</schedule>

</root>

xsl file
----------------------------------------
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="root">
   <xsl:for-each select="schedule[@category='title' and @type='title1'] ">

   <xsl:value-of select="."/>

   </xsl:for-each>
</xsl:template>

</xsl:stylesheet>


> and i want to get the text where category = title and type =
> title1

btw, i would avoid stating something like XSLQuery, in a subject line, as it
could be misconstrued to be XMLQuery, a completely different thing

chow, jim fuller


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