Subject: Re: Can I take only parts from node value?
From: "Robert Koberg" <rob@xxxxxxxxxx>
Date: Tue, 19 Feb 2002 08:07:32 -0800
|
If they are always in that format you could use the substring function. I
would leave it this format because it will be easier to sort.
best,
-Rob
----- Original Message -----
From: "jp" <jp@xxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, February 19, 2002 7:58 AM
Subject: Can I take only parts from node value?
> Hi,
>
> If I have XML-tag like this:
>
> <today date="200202190800" />
>
> and I want output:
>
> Time is 08:00
> Date is 19.02
> Year is 2002
>
> How can I do this with XSL/T? Or should I change XML output?
>
> Regs,
> -JP
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
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- regd: XSLT in SAXON
- laksh vr - Tue, 19 Feb 2002 08:59:19 -0500 (EST)
- Michael Kay - Tue, 19 Feb 2002 09:22:11 -0500 (EST)
- jp - Tue, 19 Feb 2002 10:55:39 -0500 (EST)
- Robert Koberg - Tue, 19 Feb 2002 11:07:31 -0500 (EST) <=
- Oleg Tkachenko - Tue, 19 Feb 2002 11:15:51 -0500 (EST)
- Michael Kay - Tue, 19 Feb 2002 12:02:39 -0500 (EST)
- jp - Tue, 19 Feb 2002 12:25:05 -0500 (EST)
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