Subject: value of xsl:param in xsl:sort
From: "Kunal H. Parikh" <kunal@xxxxxxxxxx>
Date: Thu, 14 Feb 2002 15:41:05 +1100
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Hi !
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<xsl:param name="sortByElement">AuthorList/Author/Name</xsl:param>
<xsl:sort select="$sortByElement" order="ascending"></xsl:sort>
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The above code does not seem to be replacing the $sortByElement for the
parameter.
But, if I replace "$sortByElement" with "AuthorList/Author/Name", everything
works out just fine.
Can someone please suggest what mistake I am making ?
TIA,
Kunal
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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