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Once again the structure is <A> <B><C/><C/>...<C/></B> <B><C/><C/>...<C/></B> . . </A> Thanks to Joerg Heinicke, I managed to pass the position of the B element to the C elements. Further, I now need a globally unique number for C. For that, I've been using (within C): select="count(../preceding-sibling::B/C)+position()" But this seems very inefficient, and it looks like performance degrades over time (may be an implementation issue?). Any hints on a less costly (constant time perhaps) way of getting enumerated the C elements? Thanks, Morten XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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