Subject: Re: Sorting a variable that contains a nodeset
From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>
Date: Thu, 10 Jan 2002 16:23:03 +0000
|
Hi Rafael,
> I have a variable containing a nodeset as <xsl:variable name="var"
> select="//ARTICULO"/> and I want to order this nodeset by the node
> 'NOMBRE_FAMILIA'. How can I perform it? Exists any function that
> sorts the variable?
Because collections of nodes are *sets* in XSLT 1.0, they are
unordered by definition. But you can process the nodes in the set in a
particular order using xsl:sort when you use xsl:for-each:
<xsl:for-each select="$var">
<xsl:sort select="NOMBRE_FAMILIA" data-type="number" />
...
</xsl:for-each>
Or when you apply templates:
<xsl:apply-templates select="$var">
<xsl:sort select="NOMBRE_FAMILIA" data-type="number" />
</xsl:apply-templates>
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|