Subject: Re: Problem in xsl:for-each
From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>
Date: Thu, 10 Jan 2002 16:58:40 +0000
|
Hi Jam,
> I'm trying to access to all items in node 'Parrafo'.
> Variable $Nombre_Fichero contains a valid filename .
> This XSL does not output all elements. (This is the real problem )
>
> <xsl:for-each
> select="$Nombre_Fichero//Documento/Noticia/Cuerpo/Parrafo">
> <xsl:copy-of select="$Nombre_Fichero//."/>
> <br>
> </br>
> </xsl:for-each>
Perhaps you want:
<xsl:for-each
select="$Nombre_Fichero//Documento/Noticia/Cuerpo/Parrafo">
<xsl:copy-of select="." />
<br />
</xsl:for-each>
This will give you a copy of each Parrafo element, separated by br
elements.
But you said that $Nombre_Fichero contained a filename (and not a node
set, which is what it would have to hold for the above file to work),
so possibly you're actually after:
<xsl:for-each
select="document($Nombre_Fichero)//Documento/Noticia/Cuerpo/Parrafo">
<xsl:copy-of select="." />
<br />
</xsl:for-each>
Feel free to post more details about your source document and the
output that you want to generate if the above doesn't work.
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
- Problem in xsl:for-each
- jam - Thu, 10 Jan 2002 11:11:14 -0500 (EST)
- Jeni Tennison - Thu, 10 Jan 2002 11:57:15 -0500 (EST) <=
- <Possible follow-ups>
- Zwetselaar M. van (Marco) - Thu, 10 Jan 2002 11:45:30 -0500 (EST)
- jam - Thu, 10 Jan 2002 12:18:59 -0500 (EST)
- jam - Thu, 10 Jan 2002 12:50:15 -0500 (EST)
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