Thanks Joerg for the example...

at the risk of being flamed badly, it is a requirement that it be written in
wd-xsl (I am modifying a large pre-written stylesheet).  It will be
rewritten in xslt for the next version, but at this time (and for this
deadline) it must stay as wd-xsl.

My wd-xsl knowledge is weak, so if anyone can help me out:

> I have the line:
>
> <graphic id="XBWQEF00F" boardno="N0011939.FAX" size="A4" rfa="(Pre
> Mod.02138)" label="2" inschlvl="3" mark="1"/>
>
> And the line:
>
> <xref xrefid="XBWQEF00F"/>
>
> When I encounter the <xref> element I want to output the 'label' attribute
> >from the corresponding graphic element.
>
> Any ideas?






-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Joerg
Heinicke
Sent: Thursday, January 31, 2002 11:00 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  need xpath


Hello Andrew,

the would be the id()-function, but you need to have a DTD than, which sets
your id-attribute to ID:

<xsl:template match="xref">
    <xsl:value-of select="id(@xrefid)/@label"/>
</xsl:template>

The second best method is using keys (possible without DTD):

<xsl:key name="graphics" match="graphic" use="@id"/>

<xsl:template match="xref">
    <xsl:value-of select="key('graphics',@xrefid)/@label"/>
</xsl:template>

Regards,

Joerg

----- Original Message -----
From: "Andrew Welch" <andrew@xxxxxxxxxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, January 31, 2002 11:42 AM
Subject:  need xpath


>
> I have the line:
>
> <graphic id="XBWQEF00F" boardno="N0011939.FAX" size="A4" rfa="(Pre
> Mod.02138)" label="2" inschlvl="3" mark="1"/>
>
> And the line:
>
> <xref xrefid="XBWQEF00F"/>
>
> When I encounter the <xref> element I want to output the 'label' attribute
> >from the corresponding graphic element.
>
> Any ideas?
>
> Cheers
>
> andrew


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 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list